-2x^2+480x=0

Solution for -2x^2+480x=0 equation:

-2x^2+480x=0

a = -2; b = 480; c = 0;
Δ = b2-4ac
Δ = 4802-4·(-2)·0
Δ = 230400
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{230400}=480$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(480)-480}{2*-2}=\frac{-960}{-4}
=+240
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(480)+480}{2*-2}=\frac{0}{-4}
=0
$